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设方程x²+1993x-1994=0和(1994x²)-1993*1995x-1=0的两个较小根次是α,β,则α*β=()
人气:486 ℃ 时间:2020-01-31 20:07:37
解答
(x-1)(x+1994)=0x=-1994
(1994^2)x^2-(1994^2-1)x-1=0(1994^2)x^2-(1994^2)x+x-1=0 [(1994^2)x+1](x-1)=0x=-1/1994^2
-1994*-1/1994^2=1/1994
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