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-2xy-x²-y² (x²-2y)²-(1-2y)² 分解因式
人气:372 ℃ 时间:2020-05-22 21:46:07
解答
-2xy-x²-y²=-(x²+2xy+y²)=-(x+y)²(x²-2y)²-(1-2y)²=(x²-2y+1-2y)(x²-2y-1+2y)=(x²-4y+1)(x²-1)=(x²-4y+1)(x+1)(x-1)
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