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数学
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已知x、y的方程组3(x²+y²)-5xy=6,2(x²+y²)+xy=17,求xy(x²+y²)的值
人气:104 ℃ 时间:2020-04-10 23:26:19
解答
方程组
3(x²+y²)-5xy=6(1)
2(x²+y²)+xy=17 (2)
(1)*2-(2)*3
-13xy=-39
xy=3
(1)+(2)*5
13(x²+y²)=91
(x²+y²)=7
所以:xy(x²+y²)=3*7=21
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