∫[1,e](1+inx)/xdx定积分谢谢了
人气:225 ℃ 时间:2020-06-15 09:36:15
解答
∫[1,e](1+inx)/xdx
=∫[1,e](1+inx)dlnx
=∫[1,e](1+inx)d(1+inx)
=(1+inx)²/2 [1,e]
=(1+lne)²/2-(1+ln1)²/2
=3/2
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