求函数函数y=Asin(wx+φ))(A≠0,w>0)的单调区间
解析：∵函数y=Asin(wx+φ))(A≠0,w>0)
单调增区间：
2kπ-π/2<=wx+φ<=2kπ+π/2==>2kπ/w-(π+2φ)/(2w)<=x <=2kπ/w+(π-2φ)/(2w)
单调减区间：
2kπ+π/2<=wx+φ<=2kπ+3π/2==>2kπ/w+(π-2φ)/(2w)<=x <=2kπ/w+(3π-2φ)/(2w)