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1/(cos x)^2怎么积分,
人气:444 ℃ 时间:2020-06-13 03:16:17
解答
∫dx/(cosx^2)
=∫(sinx^2+cosx^2)dx/cosx^2
=∫(sinxd-cosx)/cosx^2+∫dsinx/cosx
=∫sinxd(1/cosx)+∫dsinx/cosx
=sinx/cosx-∫dsinx/cosx+∫dsinx/cosx+C
=tanx+C
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