如果多项式x^5-（a+6）x^4+7x^2+(b-4)x-9中不含x的4次方和x项,试求下列式子的值 （1）a^2+2ab+b^2
(2)(a+b)^2
有（1）（2）两小题的结果,你有什么发现?
人气：181 ℃ 时间：2019-10-18 09:04:53
解答
要使x^5-（a+6）x^4+7x^2+(b-4)x-9中不含x的4次方和x项,必须使a+6=0,b-4=0
a=-6,b=4 代入（1）（2）式子,两式子结果相等.
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