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(sin x-1)/(cos x+2) 求值域
不用数形结合,转化为定点到定圆的斜率.用定义域转化为方程有解.
人气:475 ℃ 时间:2020-10-01 23:40:19
解答
令,Y=(sin x-1)/(cos x+2) Y*cosx+2y=sinx-1,sinx-ycosx=2y+1,√(1+y^2)*sin(x-b)=2y+1,sin(x-b)=(2y+1)/[√(1+y^2)]而,-1≤sin(x-b)≤1,即,-1≤(2y+1)/[√(1+y^2)]≤1.-4/3≤Y≤0.(sin x-1)/(cos x+2) 则,值域为:[-...
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