函数y=
的值域为( )
A. [-
,
]
B. [-
,0]
C. [0,
]
D. (0,
]
人气:491 ℃ 时间:2019-10-23 03:38:00
解答
∵y=
,
∴1+sinx=2y+ycosx,
∴sinx-ycosx=2y-1,
即:
sin(x-θ)=2y-1,
∵-
≤
sin(x-θ)≤
,
∴-
≤2y-1≤
,
解得:y∈[0,
].
故选C.
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