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解二元二次方程组 (x-1)(y+2)=0 (x+1)(y-2)=0
人气:206 ℃ 时间:2020-09-17 18:38:29
解答
(x-1)(y+2)=0
xy+2x-y-2=0 (1)
(x+1)(y-2)=0
xy-2x+y-2=0 (2)
(1)-(2)得
4x-2y=0
y=2x
(x-1)(2x+2)=0
(1) x-1=0,x=1,y=2
(2) x+1=0,x=-1,y=-2
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