(m²-1)/(m²+2m) ÷ [2-(1+m)/m]
=(m+1)(m-1)/[m(m+2)] ÷[(2m-1-m)/m]
=(m+1)(m-1)/[m(m+2)] × m/(m-1)
=(m+1)/(m+2)
解不等式m+2＜1得：m-3,即m>-2
所以满足不等式组的m的解为：-2