n（Cu）=

1.92g

64g/mol

=0.03mol，n（NO₂+2NO）=

1.12L

22.4L/mol

=0.05mol，
设n（NO）=xmol，n（NO₂）=ymol，则
 Cu+4HNO₃（浓）=Cu（NO₃）₂+2NO₂↑+2H₂O
0.5y                       y
 3Cu+8HNO₃（稀）=3Cu（NO₃）₂+2NO↑+4H₂O
 1.5x                        x

x+y=0.05 1.5x+0.5y=0.03

，解得x=0.005，y=0.045，
v（NO）=0.005×22.4×1000=112mL，
故选A．