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求sin6次方x+cos6次方x+3sin平方xcos平方x+4的值?
人气:179 ℃ 时间:2019-11-15 07:53:52
解答
sin^6x+cos^6x+3sin^2xcos^2x+4=(sin^2x+cos^2)(sin^4x-sin^2xcos^2x+cos^4x)+3sin^2xcos^2x+4
=(sin^2+cos^2x)^2-3sin^2xcos^2x+3sin^2xcos^2x+4
=1+4
=5
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