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等差数列 A1+A2+A3=6,A2+A3+A4=7,A3+A4+A5=
人气:218 ℃ 时间:2020-05-28 04:35:17
解答
a1+a2+a3=3a2=6
a2=2
a2+a3+a4=3a3=7
a3=7/3
a3+a4+a5
=3a4
=3(a3+(a3-a2))
=3(7/3+(7/3-2))
=3(7/3+1/3)
=8
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