化简:根号(x的平方+x的平方分之1-2)(-1
人气:485 ℃ 时间:2019-11-19 13:41:15
解答
x^2+1/x^2-2=1/x^2 * [x^4-2x^2+1]=1/x^2 * (x^2-1)^2
因此:
sqrt(x^2+1/x^2-2)= sqrt(1/x^2 * (x^2-1)^2)
= 1/|x| * |x^2-1|
= -1/x * (1-x^2)
= (x^2-1)/x
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