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(-x^2y)^3/(xy)^3*(-2x^3y^2)^3
-(5x^2y+4xy^2+xy)/xy
先求值在化简:(x^5+3x^3)/x^3-(x+1)^2,其中x=-1/2
人气:277 ℃ 时间:2020-03-15 23:15:19
解答
(-x^2y)^3/(xy)^3*(-2x^3y^2)^3=-x^6y^3/x^3y^3×(-8x^9y^6)=8x^12y^6 -(5x^2y+4xy^2+xy)/xy=-5x-4y-1 先求值在化简:(x^5+3x^3)/x^3-(x+1)^2,其中x=-1/2(x^5+3x^3)/x^3-(x+1)^2,=x²+3-x²-2x-1=-2x+2当x...
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