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求证:1-cos^2a/sina-cosa - sina+cosa/tan^2a-1=sina+cosa
人气:445 ℃ 时间:2020-02-03 04:15:15
解答
原式=sin^2a/(sina-cosa) -(sina+cosa)/(sin^2a/cos^2a -1)
=sin^2a/(sina-cosa)-(sina+cosa)/[(sina+cosa)(sina-cosa)}/cos^2a
=sin^2a/(sina-cosa)-cos^2a/(sina-cosa)
=sina+cosa
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