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解方程 x(x+1)(x²-2x-4)=0 x³-2x+1=0 x的4次方+8x³+14x²+8x+1=0
人气:467 ℃ 时间:2020-03-29 01:40:37
解答
x(x+1)(x²-2x-4)=0 x1=0x2=-1x²-2x-4=0x²-2x+1=5(x-1)²=5x3=1+√5x4=1-√5x³-2x+1=0x³-x-x+1=0x(x²-1)-(x-1)=0x(x+1)(x-1)-(x-1)=0(x²+x-1))(x-1)=0x1=1x²+x-1=0x...
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