已知5根号3sinx+5cosx=6,根号2siny+根号6cosy=1且x属于(0,π/3),y属于(π/6,π/2),求cos(x+y)
人气:320 ℃ 时间:2020-01-30 10:26:06
解答
5√3sinx+5cosx=6,5√3sinx/10+5cosx/10=6/10√3/2*sinx+1/2*cosx=3/5sinxcosπ/6+cosxsinπ/6=3/5sin(x+π/6)=3/5x∈(0,π/3)x+π/6∈(π/6,π/2)cos(x+π/6)=4/5√2siny+√6cosy=1√2siny/√2+√6cosy/√2=1/√2si...
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