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若tanα=根号2/2 求2sinα+cosα/2sinα-cosα
人气:331 ℃ 时间:2020-03-24 15:44:22
解答
tana=√ 2/2
(2sina+cosa)/(2sina-cosa)
=(2sina/cosa+1)/(2sina/cosa-1)
=(2tana+1)/(2tana-1)
=(2*√ 2/2+1)/(2*√ 2/2-1)
=(√ 2+1)/(√ 2-1)
=3+2√ 2.
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