为求方便.令y'=p则原方程化简为p^3+2xp=y两边对x微分得：3(p^2)*dp/dx+2p+2x*dp/dx=p 化简得3(p^2)dp+pdx+2xdp=0（*）（1）若p=0即y'=0 方程（*）显然成立,代入原方程得解y=0（2）若p不为0, 则方程（*）两端同乘以p ...