(√3+i)^(-3)
=1/(√3+i)^3
=1/(√3+i)^2(√3+i)
=1/(2+2√3i)(√3+i)
=1/2(1+√3i)(√3+i)
=1/2(√3+i+3i-√3)
=1/2(4i)
=1/8i
=i/(-8)
=-i/8.我也算的这个，答案写的是8i，是答案错了吧？我认为是-i/8.
另一个答题者也是这个答案。