已知等差数列{an}的前n项和为Sn,且S10=12,S20=17,则S30为( )
A. 20
B. 15
C. 25
D. 30
人气:216 ℃ 时间:2020-03-24 14:23:20
解答
∵数列{an}为等差数列,∴SnS2n-SnS3n-S2n也是等差数列,
∵S10=12,S20=17,
∴S20-S10=5,S30-S20=5+(5-12)=-2
∴S30=15
故选B
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