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已知m=2005,求m/(1x2)+m/(2x3)+m/(3x4)...+m/(2003x2004)+m/(2004x2005)的值.
人气:468 ℃ 时间:2020-06-14 05:33:26
解答
m/(1×2)+m/(2×3)+m/(3×4)+...+m/(2003×2004)+m/(2004×2005)=m[1/(1×2)+1/(2×3)+1/(3×4)+...+1/(2003×2004)+1/(2004×2005)]=m(1-1/2+1/2-1/3+1/3-1/4+...+1/2003-1/2004+1/2004-1/2005)=m(1-1/2005)=2004m/...
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