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已知x+15=y+12=z+5,求x^2+y^2+z^2-xy-xz-yz
今晚要
人气:231 ℃ 时间:2020-06-09 15:16:27
解答
x^2+y^2+z^2-xy-xz-yz
=1/2(2x^2+2y^2+2z^2-2xy-2xz-2yz)
=1/2[(x-y)^2+(x-z)^2+(y-z)^2]
=1/2[(12-15)^2+(5-15)^2+(5-12)^2]
=1/2(9+100+49)
=79
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