[1/(x+1)]+[(x-3）/x]-(1/2x)=[2x+2(x-3)(x+1)-x-1]/2x(x+1)2/x+[3/（x-1）]-[3/(x-3)]=[2(x-1)(x-3)+3x(x-3)-3x(x-1)]/x(x-1)(x-3)异分母分式加减混合运算2道不行了,累死了,太难打了,你在找人出几个吧...