(X+2)(X+3)(X-4)(X-5)=144 左边分组：[(X+2)(X-4)][(X+3)(X-5)]=144 整理得：（X^2-2X-8)(X^2-2X-15)=144 换元：设X^2-2X-8=Y 则原方程可化为：Y（Y-7)=144 解得Y=16或Y=-9 再解X^2-2X-8=16和X^2-2X-8=-9 解X^2-2X-8...