> 数学 >
xy=e^x+y 确定隐函数y的导数dy/dx
人气:277 ℃ 时间:2019-08-16 23:58:18
解答
xy = e^x +y
xy' + y = e^x + y'
y'(1-x) = y -e^x
y' = (y-e^x)/(1-x)
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版