xy=e^(x+y)的隐函数导数dy/dx如何求?
人气:125 ℃ 时间:2019-10-17 06:16:37
解答
边对x求导有
y+xy' = e^(x+y) * (1+y')
解得 dy/dx =y'=(e^(x+y)-y)/ ( x-e^(x+y))
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