求z=1+根号下ln(xy)的偏导数,求求u=arctan(m的平方乘n)的偏导数.
人气:364 ℃ 时间:2020-02-06 04:12:36
解答
1.az/ax=1/2*1/√ln(xy)*1/(xy)*y=1/(2x√ln(xy))
同理:az/ay=1/(2y√ln(xy))
2.au/am=1/(1+(m^2n)^2)*n*2m=2mn/(1+m^4n^2)
au/an=1/(1+(m^2n)^2)*m^2=m^2/(1+m^4n^2)
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