> 数学 >
计算:0.125^2012×4^2011÷(2^99×0.125^33)
人气:366 ℃ 时间:2020-06-18 15:53:13
解答
0.125^2012×4^2011÷(2^99×0.125^33)
=(1/8)²º¹²×4²º¹¹÷[2^99×(1/8)³³]
=(1/4×1/2)²º¹²×4²º¹¹÷(8³³×1/8³³)
=(1/2)²º¹²×(1/2)²×(1/4)²º¹¹×4²º¹¹÷(8×1/8)³³
=(1/2)^2014
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版