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对数不等式:log(1/2) (4x^2-x)>1
人气:250 ℃ 时间:2020-02-05 01:19:59
解答
log(1/2) (4x^2-x)>1
log(1/2) (4x^2-x)>log(1/2)(1/2)
0x1/4
4x²-x -1/4
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