1/(x-3)-6/(x^2-9)+(1-x)/(6+2x)
=[2(x+3)-6×2+(1-x)(x-3)]/2(x+3)(x-3)
=(2x+6-12-x²+4x-3)/2(x+3)(x-3)
=(-x²+6x-9)/2(x+3)(x-3)
=-(x-3)²/2(x+3)(x-3)
=-(x-3)/2(x+3);
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