根号2sin(π/3-x)+根号6cos(π/3-x)
=2√2*[sin(π/3-x)(1/2)+(√3/2)cos(π/3-x)]
=2√2*[sin(π/3-x)*cos(π/3)+cos(π/3-x)*sin(π/3)]
=2√2*sin[(π/3-x)+π/3]
=2√2*sin(2π/3-x)