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计算:0.2+0.4+…+0.8+0.10+0.12+…+0.98+0.100=______.
人气:385 ℃ 时间:2020-05-20 13:41:32
解答
0.2+0.4+…+0.8+0.10+0.12+…+0.98+0.100,
=(0.2+0.8)×[(0.8-0.2)÷0.2+1]÷2+(0.10+0.98)×[(0.98-0.10)÷0.02+1]÷2+0.100,
=2+24.3+0.1,
=26.4.
故答案为:26.4.
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