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已知(a-2)²+丨b+1丨=0,求(-a-b)的2010次方+2的8次方×(-a分之1)的9次方的值
人气:297 ℃ 时间:2020-10-02 00:13:44
解答
(a-2)²+丨b+1丨=0,
所以有:
a-2=0
b+1=0
得a=2,b=-1
(-a-b)的2010次方+2的8次方×(-a分之1)的9次方
= (-2-(-1))^2010+2^8*(-1/2)^9
=(-1)^2010+2^8*(-2^(-9))
=1-2^(8-9)
=1-1/2
=1/2
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