> 数学 >
“化简( tan3/2x-tanx/2)(cosx+cos2x)/sinx”
人气:226 ℃ 时间:2020-06-16 08:42:14
解答
tan(3x/2)-tan(x/2) = [sin(3x/2)/cos(3x/2) - sin(x/2)/cos(x/2)]= (sin3x/2 cosx/2 - con3x/2 sinx/2) / cos3x/2 cosx/2其中:(sin3x/2 cosx/2 - con3x/2 sinx/2) = [(sin2x+sinx)-(sin2x-sinx)]/2 = sinx所以:ta...
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版