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Cos(180度+α)sin(-α)/tan(-α-180度)
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人气:176 ℃ 时间:2020-05-10 00:39:40
解答
cos(180°+α)*sin(-α)/tan(-α-180°)
=-cosα*(-sinα)/tan(-α)
=sinα*cosα/(-tanα)
=sinα*cosα*cosα/(-sinα)
=-(cosα)^2
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