求f(x)=x2-2ax-1在区间[0,2]上的最大值和最小值.
人气:108 ℃ 时间:2019-08-18 02:56:46
解答
f(x)=(x-a)2-1-a2,对称轴为x=a.①当a<0时,由图①可知,f(x)min=f(0)=-1,f(x)max=f(2)=3-4a.②当0≤a<1时,由图②可知,f(x)min=f(a)=-1-a2,f(x)max=f(2)=3-4a.③当1≤a≤2时,由图③可...
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