已知(b-2)/(a+1) = 4,求代数式3(b-2)/4(a+1) + (3a+3)/(b-2)的值_数学解答

已知(b-2)/(a+1) = 4,求代数式3(b-2)/4(a+1) + (3a+3)/(b-2)的值

人气：459 ℃　时间：2020-04-13 19:08:42

解答

3(b-2)/4(a+1) + (3a+3)/(b-2)
=3/4 (b-2)/(a+1)+3/[(b-2)/(a+1)]
=3/4 *4+3/4
=3+3/4
=15/4