设两数为a,ba+b=6.①ab=7.②由①得:b=6-a代入②,得:a(6-a)=7-a²+6a=7a²-6a+7=0△=36-28=8a1=(6+√8)/2=3+√2a2=(6-√8)/2=3-√2b1=6-(3+√2)=3-√2b2=6-(3-√2)=3+√2所以这两数为3+√2和3-√2...