解f(x)=2sinx(sinx+cosx)=2sin²x+2sinxcosx=sin2x-(1-2sin²x)+1=sin2x-cos2x+1=√2(√2/2sin2x-√2/2cos2x)+1=√2sin(2x-π/4)+1∵x∈[0,π]∴2x-π/4∈[-π/4,7π/4]∴sin(2x-π/4)∈[-√2/2,1]∴f(x)的...