1.若y+x/xy=3,求分式2x+3xy-2y/x-2xy-y的值.
2.“先化简,再求值:[(x-3/x+3)+(6x/X²-9)]÷1/x²-9,期中,x=-√2007错超成了“x=√2007”但他的计算结果也正确,请你解释一下这是怎么会事?急好的再加分
人气:333 ℃ 时间:2019-11-04 14:00:59
解答
1.第一道题的题目可能你抄错了2.题目应该是这样的吧.:[(x-3)/(x+3)+6x/(X²-9)]÷1/(x²-9)=[(x-3)*2+6x]/[(x+3)(x-3)]÷1/(x²-9)=(X*2-6x+9-6x)/(x²-9))×(x²-9)=x*2+9然...
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