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f(x)=4sin^2[(π+2x)/4].sinx+(cosx+sinx)(cosx-sinx)
①求最小周期
②已知常数w>0,若函数y=f(wx)在区间[-π/2,2π/3]上是增函数,求w的取值范围
③若方程f(x)(sinx-1)+a=0有解,求实数a的取值范围
人气:276 ℃ 时间:2019-10-10 06:32:07
解答
1,化简:f(x)=2(1-cos(π/2+x))sinx+(cosx)^2-(sinx)^2=2sinx+1T=2π2,f(wx)=2sin(wx)+1增区间[2kπ/w-π/2w,2kπ/w+π/2w] k是N.[-π/2,2π/3]这个区间必须是上述区间的子集.[2kπ/w-π/2w]=2π/3解得:w...
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