求数列3/1*(2^2),5/(2^2)*(3^2),7/(3^2)*(4^2),……,(2n+1)/a^2(n+1)^2的前n项和
人气:451 ℃ 时间:2020-04-04 15:04:05
解答
(2n+1)/n^2(n+1)^2 = 1/n^2 - 1/(n+1)^2
SUM(3/1*(2^2),5/(2^2)*(3^2),7/(3^2)*(4^2),……,(2n+1)/a^2(n+1)^2)
=(1/1-1/2^2)+(1/2^2-1/3^2)+(1/3^2-1/4^2)+.+(1/n^2-1/(n+1)^2)
=1-1/(n+1)^2
推荐
- 求数列1/2,3/4,5/8,7/16……2n-1/2^n,……的前n项和Sn
- 数列求和:1/2+3/4+5/8+7/16+.+(2n-1)/(2^n)
- 数列归纳法3/(1^2*2^2)+5/(2^2*3^2)+7/(3^2*4^2)+...+n^2(n+1)^2/2n+1=1-1/(n+1)^2
- 求数列1/3,3/3^2,5/3^3,...,(2n-1)/3^n的和
- 求数列1/2,3/4,5/8,7/16……2n-1/2^n前n项和
- 已知单项式0.25x的b方乘y的c方与单项式-0.125ax的m-1方的和是0.625x的n方乘y的m方
- Verify that you've entered the correct information.
- 钢铁是怎样炼成的一书中,抒发了作者怎样的思想感情?
猜你喜欢