> 数学 >
(am+bn)^2+(an-bm)^2=?
人气:393 ℃ 时间:2020-05-20 02:17:43
解答
(am+bn)^2+(an-bm)^2
=(am)^2+2abmn+(bn)^2+(bm)^2-2abmn+(an)^2
=(am)^2+(bn)^2+(bm)^2+(an)^2
=a^2(m^2+n^2)+b^2(m^2+n^2)
=(a^2+b^2)(m^2+n^2)
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版