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4x²-[2x-(x²-2x+3)-2(x²-3x)] 计算
人气：209 ℃　时间：2020-01-28 17:37:37
解答
4x²-[2x-(x²-2x+3)-2(x²-3x)]
=4x²-2x+(x²-2x+3)+2(x²-3x)]
=4x²-2x+x²-2x+3+2x²-6x
=7x²-10x+3
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