已知a不等于b,且a^2-5a-1=0,b^2-5b-1=0,则1/3a+1/3b的值为多少
说明白一点了
人气:205 ℃ 时间:2020-04-24 15:14:16
解答
a不等于b,且a^2-5a-1=0,b^2-5b-1=0
所以a和b是方程x^2-5x-1=0的两个根
a+b=5,ab=-1
1/3a+1/3b
=(1/3)*(a+b)/ab
=(1/3)*5/(-1)
=-5/3
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