这道题怎么因式分解16z^2(4x-2y)^+12z^2(y-2x)^3
人气:282 ℃ 时间:2020-01-15 23:13:30
解答
16z²(4x-2y)²+12z²(y-2x)³
=16z²[2(2x-y)]²-12z²(2x-y)³
=64z²(2x-y)²-12z²(2x-y)³
=4z²(2x-y)²[16-3(2x-y)]
=4z²(2x-y)²(3y-6x+16)对不起应该是16z^3哦。16z³(4x-2y)²+12z²(y-2x)³=16z³[2(2x-y)]²-12z²(2x-y)³=64z³(2x-y)²-12z²(2x-y)³=4z²(2x-y)²[16z-3(2x-y)]=4z²(2x-y)²(3y+16z-6x)
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