> 数学 >
∫ [cos^3(x)]/[sin^2 (x)]dx
人气:385 ℃ 时间:2020-05-11 05:39:15
解答
∫ [cos^3(x)]/[sin^2 (x)]dx
=积分:(cos^2x)/(sin^2x)dsinx
=积分:(1-sin^2x)/sin^2x)dsinx
=积分;1/sin^2xdsin^2x-积分1dsinx
=-1/sinx-sinx+C
推荐
猜你喜欢
© 2025 79432.Com All Rights Reserved.
电脑版|手机版